Bennett University 2017 Notification Released

What is Bennett University?

Bennett University is a private university started by the 'Times of India' Group, located in Greater Noida, Uttar Pradesh. Bennett University inviting applications from the eligible candidates for admission into the Engineering programmes for the academic year 2017 based on merit in JEE Mains - 2017.

Eligibility:

⇒ Min 5 Subjects in 10+2 or its equivalent examination (equivalence as defined by JEE Board). Candidates with 4 subjects in 10+2 class are not eligible.

⇒ The candidate must obtain minimum of 60% aggregate marks in three subjects to include Physics, and Mathematics (Compulsory) and one subject amongst Chemistry, Biology, Biotechnology, Computer Science, Informatics Practices and Multimedia & Web Technology

⇒ The minimum academic qualification for admission to any one of the programs is as laid down by JEE (Board). The 10+2 or its equivalent Examination must be passed in 2015, 2016 or 2017.

⇒ Candidates whose date of birth falls on or after 01,October, 1996 (Date of Birth as recorded in the High School/Secondary Education Board/University Certificate only will be taken as authentic) are only eligible to apply for admission.

Admission Procedure:

The University merit lists shall be announced based on the actual marks obtained by the candidate in Paper - 1 of JEE (Main) 2017.

The counseling may be held on line or at a specified venue, the schedule and details of which shall be announced in due course (Tentatively 23 June 2017).

Important dates:

Online application starts from	2nd week of Jan 2017
Last date of application	05th May, 2017
Merit Lists to be announced	by 14th June, 2017
Issue of offer letters thru E mail/uploading results on web site for on line counseling	within 1 day of merit lists being announced
On line Counseling/Venue based counseling	To be announced
Commencement of classes	Tentatively Mid July 2017

For further details: http://myrank.co.in/notifications/notification.php?notice_id=119

Clock Puzzle 2 (With Answers)

Puzzle-1: Where should the hour hand point to on the bottom clock?

Answer: Hour hand is pointing to 2.

Explanation: Multiply the hour hand value by 2 and add the minute hand value. This total is always 15.

Puzzle-2: What time should the bottom clock show?

Answer: Five minutes to ten

Explanation: Start with the top left clock face, and move around the others clockwise. The minute hand moves backwards by 15 minutes, then 20, then 25 etc., while the hour hand moves forward 2 hours, then 3, then 4 etc.

Puzzle-3:  Where should the hour hand point to on the bottom clock?

Answer: To the 5

Explanation: Start with the top left clockface, and move around the others in a clockwise direction. The sum of the numbers pointed to by the hour and minute hand follows the sequence 14, 15, 16, 17 and 18.

Puzzle-4: What time should the last watch show?

Answer: 6:20

Explanation: On each watch, the sum of the digits shown equals 8.

Puzzle-5: Where should the hour hand point to on the bottom clock?

Answer: The hour hand points to the 4.

Explanation: The sum of the values pointed to by the hands on each clock equals 12.

Resolution of Vectors

We can now resolve a vector A in terms of component vectors that lie along unit vectors î and ĵ. Consider a vector A that lies in x - y plane as shown in figure. We draw lines from the head of A perpendicular to the coordinate axes as in figure and get vectors A₁ and A₂ such that A₁ + A₂ = A since A₁ is parallel to î and A₂ is parallel to ĵ. we have:

A₁ = A_x î, A₂ = A_y ĵ

Where A_x and A_y are real numbers.

Thus, A = A_x î + A_y ĵ

This is represented in figure. The quantities A_x and A_y  are called x - and y - components of the vector A. note that A_x is itself not a vector, but A_x î  is a vector, and so is A_y ĵ. Using simple trigonometry, we can express A_x and A_y in terms of the magnitude of A and the angle θ  it makes with the axis:

A_x = A cos θ

A_y = A sin θ

As is clear from A_y = A sin θ a component of a vector can be positive, negative or zero depending on the value of θ.

Now, we have two ways to specify a vector A in a plane. It can be specified by:

i) Its magnitude A and the direction θ it makes with the x -axis or

ii) Its components A_x and A_y

If A and θ are given, A_x and A_y can be obtained using A_y = A sin θ. If Ax and A_y are given, A and θ can be obtained as follows:

A²_x + A²_y = A² cos² θ + A² sin² θ

A²_x + A²_y = A²

Or 

A = √ (Aₓ² + A_y²)

And tanθ = A_y/Aₓ, θ = tan⁻¹ A_y/Aₓ

A_x = A cosα, A_y = A cos β, A_z = A cos ɣ

In general, we have

A = A_x î + A_y ĵ + A_z } } k̂

The magnitude of vector A is A = √ (Aₓ² + A_y² + A_z²)

A position vector r can be expressed as r = x î + y ĵ + z} } k̂.

Where x, y and z are the components of r along x, y, z- axes, respectively.} }

All India Institutes of Medical Sciences (AIIMS) 2017 Notification Released

What is AIIMS?

The All India Institutes of Medical Sciences (AIIMS) are a group of autonomous public medical colleges of higher education in India. For the academic year - 2017, Applications are invited for Registration in the prescribed form through online mode only for the Entrance Examination for admission to the MBBS Course of AIIMS, New Delhi and six other AIIMS (Patna, Bhopal, Jodhpur, Bhubaneshwar, Rishikesh and Raipur).

Important Dates:

Sl. No	Activity	Scheduled Dates
Application and Registration
1	Online Registration of Applications on AIIMS website www.aiimsexams.org opens	Tuesday, 24th January, 2017
2	Online Registration of Applications closes on	Thursday 23rd February, 2017 at 5:00 PM
3	Status of Registration including rejection/ deficiencies in application on AIIMS website	Tuesday, 7th March, 2017
4	Last date for complying with deficiencies in application as indicated	Wednesday, 22nd March, 2017
5	Hosting / Uploading the Admit Cards on AIIMS website www.aiimsexams.org	Monday, 1st May, 2017
Computer Based Test (CBT) [Online] Entrance Examination
6	Date of Entrance Examination	Sunday, 28th May, 2017
7	Expected date of declaration of Result	Tuesday, 14th June, 2017
Proposed Counseling Schedule to be held at AIIMS, NEW DELHI
8	First Counseling	3rd to 6th July, 2017
9	Medical Examination of selected candidates for Delhi, AIIMS	7th & 8th July, 2017 (Friday & Saturday)
10	Second Counseling	3rd August, 2017   (Thursday)
11	Third Counseling	4th September, 2017 (Monday)
12	Open Counseling	27th September, 2017 (Wednesday)
Orientation Programme
13	General Orientation of New Batch including visit to CRHSP Ballabhgarh Community Development Block	10th - 12th July, 2017
14	Orientation Programme by CREST- 7 days	13th to 19th July, 2017
15	Teacher Mentors Programme Interactive Session/Feedback session about orientation Programme for 1 day	20th July, 2017
16	Candidates leave	20th July to 31st July, 2017
17	Academic Programme [Classes begin]	1st August, 2017
Admission to six other AIIMS
18	Admission details will be available in the websites of the respective institutions Counters and officials from these institutions will be available at AIIMS, New Delhi during Counseling	Expected August, 2017

Eligibility:

A. Indian Nationals:

01	AGE	• Should have attained or will attain the age of 17 (seventeen) years as on the 31st of December of the year of admission (2017) • Candidates born on or after 2nd January, 2001 are NOT eligible to apply.
02	Essential Academic Qualification	• Should have passed the 12th Class under the 10+2 Scheme/ Senior School Certificate Examination (CBSE) or Intermediate Science (I.Sc.) or an equivalent Examination of a recognized University/ Board of any Indian State with English, Physics, Chemistry and Biology as subject. • Candidates awaiting for results in 2017 are also eligible to apply AIIMS-2017
03	Minimum Marks	• The minimum aggregate of the marks in English, Physics, Chemistry and Biology obtained in the qualifying examination required for appearing in this examination are: • General and OBC candidates: 60% SC/ST/OPH Candidates: 50%.

Exam Pattern:

1. The examination shall be held on Sunday, 28^th May, 2017.

2. The duration of the examination shall be 3½ hours (three hours and thirty minutes).

3. The Online (CBT) Entrance Examination will be conducted in two shifts:

•  Morning Shift / First shift: 09:00 AM to 12:30 PM
•  Afternoon Shift / Second shift: 03:00 PM to 06:30 PM

Subject	No. of Questions
Physics	60
Biology (Botany & Zoology)	60
General Knowledge	10
Aptitude & Logical Thinking	10
Total	200
Each incorrect response will get a score of - ⅓ (minus - one - third)

For further details: http://myrank.co.in/notifications/notification.php?notice_id=127