CUEE Notification Released

What is CUEE?

CUEE is commonly referred as (Centurion University Entrance Examination) is a multi-sector, private state university from Odisha, India. It was established in 2010 and its main campus is located at Paralakhemundi in the Gajapati district. The university has been accredited by NAAC with 'A' Grade and it offers under-graduate, post-graduate and doctoral courses in the fields of engineering & technology, management and applied sciences. It has around 10,000 student. Its constituent campus is located at Jatni, on the fringes of Bhubaneswar. The university actively works in the field of sustainable community development through its various social responsibility initiatives.

Important Dates:

Sale of Information Bulletins at Notified Bank/Directly from Centurion University Offices for Entrance Test	1st Week of November 2016
Last Date of Sale of Application Form	2nd Week of March 2017
Last Date of Receipt of Application at Centurion University	3rd Week of March 2017
Admit Card on Website	Last Week of March 2017
Centurion University Entrance Examination (CUEE)	1st Week of April 2017
Declaration of Results	May 2017
Counseling for Admission	June-July 2017
Commencement of Session	August 2017

Eligibility:

Engineering & Technology (B.Tech-Regular):

• Candidates who have passed 10+2 examination or appearing in 10+2 examination are eligible to apply for B.Tech (4 years), course of the University.
• Should have studied in regular full time formal education in their schooling/college.
• Pass in 10+2 or its equivalent with at least 45% marks in Physics, Chemistry and Mathematics taken together.
• Should have born on or after 01.07.1995.
• Entrance Test: CUEE / JEE MAIN / AIEEE or any National Level Entrance Test.

Management (BBA/B.Com):

• A pass in 10+2 (Senior Secondary) or its equivalent public examination conducted by any recognized Board of Education in India or abroad.

Agriculture Science (B.Tech AG):

• Passed or appeared in 10+2 Science/equivalent with P.C.M. 45% marks in aggregate (Minimum requirement of 40% marks is applicable to reserve category candidates)

Agriculture Science (B.Sc. AG):

• Candidate must have passed or appearing 10+2 Science / Equivalent Examination with minimum of 50% marks with PCB (40% for SC/ST category) in aggregate (Excluding 4^th Optional) are eligible for applying the exam.
• Entrance Test: CUEE / OUAT / ICAR or any National Level Entrance Test.

Bachelor of Architecture (5 Years):

• A pass in (10+2) examination from a recognized board or its equivalent subject to securing 50% marks in aggregate with mathematics as a subject at the higher secondary level and a pass in the National Aptitude Test in Architecture (NATA) conducted by the Council of Architecture (CoA), New Delhi either in 2016 or 2017. Should have born on or after 01.07.1995.

Media & Mass Communication:

• Passed or Appeared 10+2 in 2015 with any stream (Arts/Science/Commerce) are eligible for Bachelor in Media Communication Admission.

ExamPattern:

The test is of objective type have to answer a total of 80 questions.

For B.Tech. (Regular) & B. Tech. (Agri. Engg.):

Subject	No. of Questions
English	20
Physics	20
Chemistry	20
Mathematics	20
Total	80

For B.Sc. (Ag.) course:

Subject	No. of Questions
English	20
Physics	20
Chemistry	20
Biology	20
Total	80

Mode of Exam: ONLINE / PEN & PAPER BASED

For further details: http://myrank.co.in/notifications/notification.php?notice_id=71

Elasticity

Elastic Property of Matter:

(1) Elasticity: The property of matter by virtue of which a body tends to regain its original shape and size after the removal of deforming force is called elasticity.

(2) Plasticity: The property of matter by virtue of which it does not regain its original shape and size after the removal of deforming force is called plasticity.

(3) Perfectly elastic body: If on the removal of deforming forces the body regain its original configuration completely it is said to be perfectly elastic.

A quartz fibre and phosphor bronze (an alloy of copper containing 4% to 10% tin, 0.05% to 1% phosphorus) is the nearest approach to the perfectly elastic body.

(4) Perfectly plastic body: If the body does not have any tendency to recover its original configuration, on the removal of deforming force, it is said to be perfectly plastic.

Paraffin wax, wet clay are the nearest approach to the perfectly plastic body.

Practically there is no material which is either perfectly elastic or perfectly plastic and the behavior of actual bodies lies between the two extremes.

(5) Reason of elasticity: In a solids, atoms and molecules are arranged in such a way that each molecule is acted upon by the forces due to neighboring molecules. These forces are known as inter molecular forces.

For simplicity, the two molecules in their equilibrium positions (at inter-molecular distance r = r₀) are shown by connecting them with a spring.

In fact, the spring connecting the two molecules represents the inter-molecular force between them. On applying the deforming forces, the molecules either come closer or go far apart from each other and restoring forces are developed. 

When the deforming force is removed, these restoring forces bring the molecules of the solid to their respective equilibrium position (r = r₀) and hence the body regains its original form.

(6) Elastic limit: Elastic bodies show their property of elasticity up to a certain value of deforming force. If we go on increasing the deforming force then a stage is reached when on removing the force, the body will not return to its original state. 

The maximum deforming force up to which a body retains its property of elasticity is called elastic limit of the material of body.

Elastic limit is the property of a body whereas elasticity is the property of material of the body.

(7) Elastic fatigue: The temporary loss of elastic properties because of the action of repeated alternating deforming force is called elastic fatigue. It is due to this reason

a.      Bridges are declared unsafe after a long time of their use.

b.      Spring balances show wrong readings after they have been used for a long time.

c.       We are able to break the wire by repeated bending.

(8) Elastic after effect: The time delay in which the substance regains its original condition after the removal of deforming force is called elastic after effect. It is the time for which restoring forces are present after the removal of the deforming force it is negligible for perfectly elastic substance, like quartz, phosphor bronze and large for glass fiber.

Stress: 
When a force is applied on a body there will be relative displacement of the particles and due to property of elasticity an internal restoring force is developed which tends to restore the body to its original state.

The internal restoring force acting per unit area of cross section of the deformed body is called stress.

At equilibrium, restoring force is equal in magnitude to external force, stress can therefore also be defined as external force per unit area on a body that tends to cause it to deform.

If external force F is applied on the area A of a body then, 

                                        Stress = Force/Area = F/A

Units: N/m² (S.I.), dyne/cm² (C.G.S.)

Dimension: [ML^-1T^-2]

Stress developed in a body depends upon how the external forces are applied over it.

On this basis there are two types of stresses: Normal and Shear or tangential stress

(1) Normal stress: Here the force is applied normal to the surface. It is again of two types: Longitudinal and Bulk or volume stress

(i) Longitudinal stress:

a.      It occurs only in solids and comes in picture when one of the three dimensions viz. length, breadth, height is much greater than other two.

b.      Deforming force is applied parallel to the length and causes increase in length.

c.       Area taken for calculation of stress is area of cross section.

d.      Longitudinal stress produced due to increase in length of a body under a deforming force is called tensile stress.

e.      Longitudinal stress produced due to decrease in length of a body under a deforming force is called compressional stress.

(ii) Bulk or Volume stress:

a.      It occurs in solids, liquids or gases.

b.      In case of fluids only bulk stress can be found.

c.       It produces change in volume and density, shape remaining same.

d.      Deforming force is applied normal to surface at all points.

e.      Area for calculation of stress is the complete surface area perpendicular to the applied forces.

f.        It is equal to change in pressure because change in pressure is responsible for change in volume.

(2) Shear or tangential stress: It comes in picture when successive layers of solid move on each other i.e. when there is a relative displacement between various layers of solid.

a.      Here deforming force is applied tangential to one of the faces.

b.      Area for calculation is the area of the face on which force is applied.

c.       It produces change in shape, volume remaining the same.

Difference between Pressure and Stress
Pressure	Stress
Pressure is always normal to the area.	Stress can be normal or tangential.
Always compressive in nature.	May be compressive or tensile in nature.

UPESEAT Notification Released

What is UPESEAT?

UPESEAT is commonly referred as University of Petroleum and Energy Studies Engineering Aptitude Test. University of Petroleum and Energy Studies (UPES) was established in the year 2003 through UPES Act, 2003 of the State Legislature of Uttarakhand.

Eligibility:

Age Criteria:

Only candidates whose date of birth falls on or after October 1, 1995 are eligible to apply for admission. Date of Birth as recorded in the Secondary Education Board only will be taken as authentic.

Examination Pathway:

Eligibility Criteria	Admission Criteria
Minimum 60% marks at Higher & Senior Secondary level (10th & 12th) and Minimum 60% aggregate in Physics, Chemistry & Mathematics at Senior Secondary level (12th)	UPES Engineering Aptitude Test (UPESEAT) Exam will be conducted in May, 2017. Dates for the exam will be announced in November, 2016

Non- Examination Pathway through Board Merit / JEE Merit (Subject to number of seats allotted)

Eligibility Criteria

Admission Criteria

Board Merit Minimum 80% marks at Higher & Senior Secondary level (10th & 12th) and minimum 80% aggregate in Physics, Chemistry & Mathematics at Senior Secondary level (12th class) OR JEE Merit (a) Minimum 60% marks at Higher & Senior Secondary level (10th & 12th) and minimum 60% aggregate in Physics, Chemistry & Mathematics at Senior Secondary level (12th class). (b) JEE Merit cut off will be announced after JEE Exam 2017.

Centralized Counseling through Merit Ranking

Up to 20% seats shall be filled through Board Merit / JEE Merit category. In case of seats following vacant in this category; UPES has the right to fill these through UPES Examination. University also reserves the right to conduct further physical (paper pencil test) / online test for admission

Important Dates:

Sale of Applications starts from	10th November, 2016
Last date of submission applications	1st week of May, 2017
Download of admit cards	2nd week of May, 2017
UPES Exam	3rd week of May, 2017
Results	Last week of May, 2017
Counselling	2nd or 3rd week of June, 2017

Exam Pattern:

Test Duration:            3 Hrs.
Subjects	Marks
Mathematics	50
Physics	50
Chemistry	50
English Language Comprehension	30
Current Affairs Awareness	20
Total	200

Mode of Exam: ONLINE

For further details: http://myrank.co.in/notifications/notification.php?notice_id=72

Locus and its equations of co-ordinates

Definition of Locus:

The curve described by a point which moves under given condition or conditions is called its locus.

Equation to the locus of a point:

The equation to the locus of a point is the relation which is satisfied by the coordinates of every point on the locus of the point.

Algorithm to find the locus of a point:

1. Assume the coordinates of the point (h, k) whose locus to be found.
2. Write the given condition in mathematical form involving h, k.
3. Eliminate the variables if any.
4. Replace h by x and k by y in the result (3).

SOME USEFUL POINTS:

1.   In order to prove that a given figure is a

• Square, prove that the four sides are equal and the diagonals are also equal.
• Rhombus, prove that the four sides are equal.
• Rectangle, prove that opposite sides are equal and the diagonals are also equal.
• A parallelogram, prove that the opposite sides are equal.
• Parallelogram but not a rectangle, prove that its opposite sides are equal but the diagonals are not equal.
• A rhombus but not a square, prove that it’s all sides are equal but the diagonals are not equal.

2.   For three points to be collinear, prove that the sum of the distance between two pairs of points, is equal to the third pair of points.

Example 1: Find the locus of the point which is equidistant to the coordinate axes.

Sol: Let P(x₁, y₁) be a point in the locus

The distance from P to x-axis is |y₁|

The distance from P to y-axis is |x₁|

Given condition is |y₁| = |x₁| ⇒ y²₁ = x²₁ ⇒ x²₁ – y²₁ = 0

The equation to the locus of P is x² – y² = 0

Example 2: The ends of the hypotenuse of a right-angled triangle are (0, 6), (6, 0). Find the locus of the third vertex?

Sol: Let A (0, 6), B (6, 0) be the ends of the hypotenuse and P (x, y) be the third vertex.

Given condition is ÐAPB = 90⁰ ⇒ PA² + PB² = AB²

⇒ x² + (y - 6) ² + (x - 6) ² + y² = 6² + 6² 

⇒ x² + y² – 12y + 36 + x² – 12x + 36 + y² = 72

⇒ 2x² + 2y² – 12x – 12y = 0

⇒ x² + y² – 6x – 6y = 0

∴ The locus of P is x² + y² – 6x – 6y = 0