EQUALITY OF MATRICES
DEFINITION:
Two
matrices A = [aij] mxn And B = [bij] mxn
are said to be equal if
- m=r, i.e., the number of rows in A equals the number of rows in B
- n=s, i.e., the number of columns in A equals the number of columns in B
- aij=bij for i=1,2,..., in and j=1,2,....,n
If two matrices A and B are equal, we write A = B, otherwise we write A # B.
ILLUSTRATION 1:
ILLUSTRATION 2:
SOLUTION
Since the corresponding elements of two equal matrices are equal.
Therefore,
x — y = —1, 2x -V z = 5, 2x — y = 0, 3z w = 13.
Solving the equation x-y=-1 and 2x-y=0 as simultaneous
linear equations, we get x=1,y=2.
Now, putting x=1 in 2x+z=5, we get z=3.
Substituting z=3 in 3z+w=13, we obtain w=4.
Substituting z=3 in 3z+w=13, we obtain w=4.
Thus, the given matrices are equal if x=1, y=2, z=3 and w=4.
ILLUSTRATION 3:
Find the values of x,y,z an a which satisfy the matrix
equation.
PROOF:
Since the corresponding elements of two equal matrices are
equal,
Therefore,
x + 3 = 0, 2y x = —7,
z — 1 = 3 and 4a - 6 = 2a.
Solving these equations, we get
a = 3, x = —3, y = —2, z = 4.
ADDITION OF MATRICES
DEFINITION:
Let
A, B be two matrices, each of order m x n. Then their sum A+B is a matrix of
order m x n and is obtained by adding the corresponding element of A and B.
Thus, if A = [aij] mxn and B = [bij]
mxn are two matrices of the same order, their sum A+B is defined to be
the matrix of order m x n such that (A+ B) ij = + bij for i =1, 2,…,
m and j =1, 2,…, n
NOTE: The sum of
two matrices is defined only when they are of the same order.
ILLUSTRATION 1:
A+B is not defined, because A and B are not of the same
order.
ILLUSTRATION 3:
For the following pairs of matrices A-FB is not defined because they are of
different orders:
PROPERTIES OF MATRIX
ADDITION
i. Matrix addition is commutative
i.e., if A and B are two m x n matrices, then A+B=B+A.
Existence of Inverse
For every matrix A = [aij] mxn there
exists a matrix [—aij] mxn, denoted by -A, such that A+
(-A) = 0 = (-A) + A.
MULTIPLICATION OF A
MATRIX BY A SCALAR
DEFINITION
Let A
= [aij] be an m x n matrix and k be any number called a scalar. Then
the matrix obtained by multiplying every element of A by k is called the scalar
multiple of A by k and is denoted by kA.
Thus, kA = [kaij] mxn.
Thus, kA = [kaij] mxn.
SUBTRACTION OF
MATRICES
DEFINITION
For
two matrices A and B of the same order, we define A—B=A + (—B).
ILLUSTRATION 2:
SOLUTION
We have.
3A-2B= 3A + (-2) B
MULTIPLICATION OF
MATRICES
Two matrices A and B are conformable for the product AB if
the number of column in A(pre-multiplier) is same as the number of tows in B
(post-multiplier).
find AB and BA and show that AB ≠ BA.
SOLUTION
Here, A is a 2 x 3 matrix and B is a 3 x 2 matrix. So, AB
exists and it is of order 2 x 2.
Again, B is a 3 x 2 matrix and A is a 2 x 3 matrix. So, BA
exists and it is of order 3 x 3.
Now,
Hence, AB ≠ BA.
PROPERTIES OF MATRIX
MULTIPLICATION
- Matrix multiplication is not commutative in general.
- Matrix multiplication is associative i.e. (AB) C=A (BC), whenever both sides are defined.
- Matrix multiplication is distributive over matrix addition i.e.,
- A (B + C) = AB + AC,
- (A + B) C = AB + AC,
whenever both sides of equality are defined. - If A is an m x n matrix, then Im A = A = A In
- The product of two matrices can be the null matrix while neither of them is the null matrix. For example, if
while neither A nor B is the null matrix
- If A is m x n matrix and 0 is a null matrix, then
- AmxnOnxp = Omxp
- OpxmAmxn = Opxn
TRANSPOE OF A MATRIX
DEFINITION
Let A=
[aij] be an m x n matrix. Then the transpose of A, denoted by AT
or A', is an n x m matrix such that
(AT )ij=
aij for all i=1,2,...,m’ j=1,2,...,n.
Thus, AT is obtained from A by changing its rows
into columns and its columns into rows. For example, if
PROPERTIES OF
TRANSPOSE
Let A and B be two matrices. Then.
- (AT) T = A
- (A + B) T = AT + BT, A and B being of the same order.
- (KA) T = kAT, k be any scalar (real or complex)
- (AB) T = BTAT, A and B being conformable for the product AB.
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