If no external
torque is acting upon a body rotating about an axis, then the angular momentum
of the body remains constant, that is,
J = I ω = constant
This is called
the ‘law of conservation of angular momentum’. If I decreases, ω increases and
vice versa.
Proof:
We have read
above that when a body rotates about an axis under the action of an external torque
τ, then the rate of change of angular momentum of the body is equal to the
torque; that is,
If the external torque is zero (τ = 0), then
or
dJ = 0
or
J = constant.
Example 1:
Suppose a ball is
tied at one end of a cord whose other end passes through a vertical hollow tube.
The tube is held in one hand and the cord in the other. The ball is set into
rotation in a horizontal circle. If the cord is pulled down, shortening the
radius of the circular path of the ball; then the ball rotates faster than
before. The reason is that by shortening the radius of the circle, the moment
of inertia of the ball about the axis of rotation decreases. Hence, by the law
of conservation of angular momentum, the angular velocity of the hall about the
axis of rotation increases.
Example 2:
When a driver jumps into water from a height,
he does not keep his body straight but pulls in his arms and legs towards the
centre of his body. On doing so, the moment of inertia I of his body decreases.
But since the angular momentum Iω remains constant, his angular velocity ω correspondingly
increases. Hence during jumping he can rotate his body in the air.
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