We
can now resolve a vector A in terms of component vectors that lie along unit vectors î and ĵ. Consider a vector A that lies in x - y
plane as shown in figure. We draw lines from the head of A perpendicular to the
coordinate axes as in figure and get vectors A1 and A2
such that A1 + A2 = A since A1 is parallel to
î and A2 is parallel to ĵ. we have:
A1
= Ax î, A2 = Ay ĵ
Where
Ax and Ay are real numbers.
Thus,
A = Ax î + Ay ĵ
This
is represented in figure. The quantities Ax and Ay are called x - and y - components of the
vector A. note that Ax is itself not a vector, but Ax î is a vector, and so is Ay ĵ. Using
simple trigonometry, we can express Ax and Ay in terms of
the magnitude of A and the angle θ it makes
with the axis:
Ax
= A cos θ
Ay
= A sin θ
As
is clear from Ay = A sin θ a component of a vector can be positive,
negative or zero depending on the value of θ.
Now,
we have two ways to specify a vector A in a plane. It can be specified by:
i)
Its magnitude A and the direction θ it makes with the x -axis or
ii)
Its components Ax and Ay
If
A and θ are given, Ax and Ay can be obtained using Ay
= A sin θ. If Ax and Ay are given, A and θ can be obtained as
follows:
A2x
+ A2y = A2 cos2 θ + A2
sin2 θ
A2x
+ A2y = A2
Or
A = √ (Aₓ² + Ay²)
A = √ (Aₓ² + Ay²)
And
tanθ = Ay/Aₓ, θ = tan⁻¹ Ay/Aₓ
Ax = A cosα, Ay = A cos β, Az = A cos ɣ
In general, we have
In general, we have
A
= Ax î + Ay ĵ + Az k̂
The magnitude of vector A is A = √ (Aₓ² + Ay²
+ Az²)
A
position vector r can be expressed as r = x î + y ĵ + z k̂.
Where x, y and z are the components of r along x, y, z- axes, respectively.
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